Engineering :: Strength Of Materials
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181. |
The yield point in fatique loading as compared to the yield point in static loading is |
A. |
Half |
B. |
One fourth |
C. |
Same |
D. |
Higher |
E. |
There is no comparison between the two |
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Answer: Option D
Explanation:
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182. |
A twisting couple in a shaft induces in the shaft |
A. |
Shear stress |
B. |
Bending moment |
C. |
Deflection |
D. |
All of the above |
E. |
None of the above |
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Answer: Option A
Explanation:
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183. |
The deformation of a steel bar under its own weight as compared to the deformation caused by a direct load equal to the weight of the shaft will be |
A. |
One fourth |
B. |
Half |
C. |
Same |
D. |
Double |
E. |
Four times |
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Answer: Option B
Explanation:
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184. |
A type of riveted joint in which the rivets in the adjacent rows are staggered and the outer-most row has only rivert, is known as |
A. |
Zig-zag riveting |
B. |
Butt-riveting |
C. |
Chain riveting |
D. |
Diamond riveting |
E. |
Criss-cross riveting |
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Answer: Option D
Explanation:
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185. |
Diamond riveting is generally used for |
A. |
Butt joints |
B. |
Lap joints |
C. |
Revised joints for dissimilar materials |
D. |
Riveted joints for materials of different thickness |
E. |
None of the above |
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Answer: Option A
Explanation:
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186. |
The weakness section of a diamond riveting is the section which passes through |
A. |
The first row |
B. |
Row with maximum rivets |
C. |
Middle row |
D. |
End row with one rivet only |
E. |
All rows have same strength |
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Answer: Option D
Explanation:
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187. |
The moment of inertia of an area will be least with respect to |
A. |
Central axis |
B. |
Horizontal axis |
C. |
Vertical axis |
D. |
Moment of area is same through all axes |
E. |
Moment of area does not depend on axes |
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Answer: Option A
Explanation:
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188. |
A perfect frame has N joints. The number of members should not be less than |
Answer: Option C
Explanation:
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189. |
The ratio of shear modulus to the modulus of elasticity when Poisson's ratio is 0.25 will be |
Answer: Option E
Explanation:
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190. |
The ratio of maximum shear stress to average shear stress in case of a circular beam transmitting power is equal to |
Answer: Option D
Explanation:
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