Engineering :: Machine Design
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181. |
In order to minimise jerks, the type of cam used is |
A. |
Cycloidal |
B. |
S.H.M. |
C. |
Parabolic |
D. |
Cylindrical |
E. |
Hyperbolic |
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Answer: Option A
Explanation:
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182. |
The purpose of providing multiple collars on a flat collar pivot bearing is to |
A. |
Increase frictional resistance |
B. |
Establish self-substaining bearing condition |
C. |
Distribute the frictional load because of limiting frictional resistance |
D. |
Distribute the axial load becase of limiting bearing pressure on a collar |
E. |
None of the above |
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Answer: Option D
Explanation:
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183. |
In above problem the cone pitch angle of the pinion will be |
A. |
tan-1 0.5 |
B. |
tan-1 2.0 |
C. |
sin-1 0.5 |
D. |
sin-1 2.0 |
E. |
cos-1 0.5 |
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Answer: Option C
Explanation:
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184. |
The 'crowning' of flat pulleys is generally done |
A. |
To rduce the belt friction |
B. |
To prevent belt joint from damaging the belt surface |
C. |
To prevent the belt from running off the pulley |
D. |
In case of cross belt drives only |
E. |
None of the above |
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Answer: Option C
Explanation:
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185. |
In case of Vee belt |
A. |
The belt should touch the bottom of groove in the fulley |
B. |
The belt should not touch the bottom of groove in the pulley |
C. |
Grooves in the pulley are generally wider than the belt |
D. |
The efficiency of transmission is less |
E. |
Tension in belt remains constant throughout |
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Answer: Option B
Explanation:
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186. |
Belt slip may occur due to |
A. |
Heavy load |
B. |
Loose belt |
C. |
Driving pulley too small |
D. |
Any of above |
E. |
None of above |
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Answer: Option D
Explanation:
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187. |
For maximum horse power transmission in belt drives the velocity of belt left such that the ration tight side driving tension/centrifugal tension is |
Answer: Option B
Explanation:
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188. |
The stretching in a belt is controlled by |
A. |
Increasing centre distance |
B. |
Increasing belt velocity |
C. |
Increasing belt thickness |
D. |
Reducing belt length |
E. |
Reducing stress in the belt |
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Answer: Option E
Explanation:
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189. |
In case of spur gears the higher pressure angle results in |
A. |
Weaker teeth |
B. |
Non-uniform motion transmission |
C. |
Begger size of gear |
D. |
Wider base and stronger teeth |
E. |
Narrow base and weaker teeth |
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Answer: Option D
Explanation:
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190. |
In case of worm and worm-wheel the maximum efficiency is obtained when |
A. |
Worm is driver |
B. |
Worm wheel is driver |
C. |
Either of the worm or worm wheel is a driver |
D. |
Depends on other factors |
E. |
None of the above |
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Answer: Option C
Explanation:
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