https://www.geekmcq.com/
CSS Solved Papers
Physics Chemistry

Entry Test MCQ :: Electrostatics


  A 25eV electron has a speed of
[A]. 2 x 106m/sec[B]. 3 x 106m/sec
[C]. 5 x 106m/sec[D]. 4 x 106m/sec

Answer: Option B


izaz ahmad said:    
 
how this is calculated ?

rowaid ikram said:    
 
how 25ev electron has a speed of 3x106m/s explain plz

zulqarnain said:    
 
how 25ev electron has a speed of 3x106m/s explain plz

maaz said:    
 
so simple 25eV is the given kinetic energy of electron which is equal to 1/2mv2..... first convert eV into joules by multiplying it by the charge of an electron and then apply the formula....1/2mv2...

pari said:    
 
please explain 25eV is = 3×10-6 m/s

Farman sahil said:    
 
K.E=1/2mv^2 K.E=2heV => 25×1.6×10^-19 J => 40×10^-19 J Now 40×10^-19=1/2 (9.11×10^-31) v^2 1/2 (v^2)=40×10^-19/9.11×10^-31 1/2 v^2 =4.3×10^12 V^2=9×10^12 V=square root of 9×10^12 V=3×10^6 m/s

Write your comments here:
Name *:     Email:

© 2012-2024 by GeekMCQ™ Technologies. All Rights Reserved | Copyright | Terms of Use & Privacy Policy | Referals

Contact us: info@geekmcq.com