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CSS Solved Papers
Physics Chemistry

Engineering :: Production Engineering

  Spindle speed in a lathe for turning a 40 cm dia rod at a cutting speed of 30 m/min would be
[A]. 100 rpm[B]. 206 rpm
[C]. 238 rpm[D]. 336 rpm
[E]. 468 rpm    

Answer: Option C
das said:    
 
S=(V/πD)*1000=(30/3.14*40)*1000=238.853rpm
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