as oxygen is taken in excess so we will not consider its moles we will take on the moles of aluminium and find the moles of product by this method 4 moles of Al gives moles of Al2O3 =2 1mole will give =2/4 0.36 will give =2/4x0.36=0.18 to do so we will form an equation first 4Al +3o2 ( after reaction )2Al2o3
