Entry Test MCQ :: Electrostatics
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A 5 ?F capacitor has a potential difference across its plates of 200 volts. The charge on the capacitor is
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2.5 x 10-8 C | [B]. |
10-5 C
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103 C | [D]. |
4 x 103 C |
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Kaustub said:
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| formula to find the charge is when PD &CAPACITY is given is
Q=C/V
check your answer |
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maya mehar said:
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| its not Q=C/V its Q=CV |
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Sirat said:
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| Answer is wrong.. it should be 10^3.
Q=CV that means 5x200 so Q=1000 or 10^3 |
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Adil Shaikh said:
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| We know that Q=CV
Data
C=5x10^-6F
V=200Volt
Q=?
Solution
Q=CV
Q=5x(10^-6)x200
Q=1000x10^-6
Q=10^3x10^-6
Q=10^-3C |
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Waqar said:
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| answer is wrong its r8 answer is 1000 ok because Q=cv |
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