Engineering :: Heat Transfer
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61. |
The Reynolds analogy states that Where f = Fanning friction factor |
A. |
NSt = f/8 |
B. |
NSt = f/2 |
C. |
NPr = f/4 |
D. |
NSt = f |
Answer: Option B
Explanation:
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62. |
Reynolds and Prandtl analogies are exactly same for |
A. |
Npr = 0.7 |
B. |
NPr = 1 |
C. |
NPr = 0.6 |
D. |
NPr > 1 |
Answer: Option B
Explanation:
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63. |
When the Prandtl number is greater than unity the thermal boundary layer |
A. |
is thinner than the hydrodynamic boundary layer |
B. |
is thicker than the hydrodynamic boundary layer |
C. |
and the hydrodynamic boundary are identical |
D. |
disappears |
Answer: Option A
Explanation:
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64. |
The Colburn/factor for heat transfer is defined as |
A. |
NSt NPr |
B. |
NSt NPr 1/3 |
C. |
NSt NPr 2/3 |
D. |
NSt NPr 3/2 |
Answer: Option C
Explanation:
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65. |
The Reynolds analogy |
A. |
applies only to fluids for which the Prandtl number is unity |
B. |
applies over a range of Parandtl numbers from 0.6 to 120 |
C. |
can be used for situations where form drag appears |
D. |
cannot be used for situations where wall drag appears |
Answer: Option A
Explanation:
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66. |
For laminar fully developed constant property flow in a pipe at uniform heat flux the Nusselt number is |
Answer: Option C
Explanation:
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67. |
For laminar fully developed constant property flow in a pipe at constant wall temperature the Nusselt number is |
Answer: Option D
Explanation:
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68. |
The Prandtl number for liquid metals is of the order of |
Answer: Option C
Explanation:
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69. |
The Colburn analogy states that where f = Fanning friction factor |
A. |
NSt = f/2 |
B. |
NSt NPr = f/2 |
C. |
NSt NPr 2/3 = f/2 |
D. |
NSt NPr 2/3 = f/8 |
Answer: Option C
Explanation:
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70. |
Dittus-Boelter equation NNu = 0.023 (NRe)0.8(NPr)n where n = 0.4 for heating the fluid and n = 0.3 for cooling the fluid is applicable for |
A. |
10.000 < NRe < 1.2 x 105 |
B. |
0.7 < NPr < 120 |
C. |
L/D > 60 |
D. |
all the above |
Answer: Option D
Explanation:
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